Convert Foot-Pound-Force to Electronvolts
Convert Foot-Pound-Force (ft·lbf) to Electronvolts (eV) instantly and accurately.
Conversion Formula
eV = ft·lbf × 8.462350028e+18
About Foot-Pound-Force
A foot-pound-force (ft·lbf) is the work done by one pound-force through one foot - exactly 1.3558179483314004 J. It is the standard torque and energy unit in US engineering. Automotive engine torque: Honda Civic ~125 lb-ft; Ford F-150 EcoBoost ~500 lb-ft. Muzzle energies: .22 LR ~140 ft·lbf; .308 Winchester ~2,600 ft·lbf; .50 BMG ~14,000 ft·lbf. Diesel pile hammers deliver 15,000-600,000 ft·lbf/blow. SAE Grade 8 bolts are specified at 7-950 ft·lbf. 1 ft·lbf = 12 in·lbf = 1.35582 J = 0.32405 cal.
About Electronvolts
An electronvolt (eV) is the kinetic energy gained by one electron accelerated through 1 volt - exactly 1.602176634 × 10⁻¹⁹ J (fixed by the 2019 SI revision). It is the natural energy unit of atomic and particle physics: visible light photons carry 1.7-3.1 eV; hydrogen ionisation requires 13.6 eV; X-ray photons span 100 eV-100 keV; protons at the LHC reach 6.5 TeV. Rest masses use eV/c²: electron 0.511 MeV, proton 938.3 MeV, Higgs boson 125 GeV. Nuclear binding energy peaks at ~8 MeV/nucleon for iron-56. 1 eV = 1.602176634 × 10⁻¹⁹ J.
Quick Reference Table
| Foot-Pound-Force (ft·lbf) | Electronvolts (eV) |
|---|---|
| 1 ft·lbf | 8.462 × 1018 eV |
| 2 ft·lbf | 1.692 × 1019 eV |
| 5 ft·lbf | 4.231 × 1019 eV |
| 10 ft·lbf | 8.462 × 1019 eV |
| 25 ft·lbf | 2.116 × 1020 eV |
| 50 ft·lbf | 4.231 × 1020 eV |
| 100 ft·lbf | 8.462 × 1020 eV |